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4b^2-11b-25=-10
We move all terms to the left:
4b^2-11b-25-(-10)=0
We add all the numbers together, and all the variables
4b^2-11b-15=0
a = 4; b = -11; c = -15;
Δ = b2-4ac
Δ = -112-4·4·(-15)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-19}{2*4}=\frac{-8}{8} =-1 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+19}{2*4}=\frac{30}{8} =3+3/4 $
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